Berapa luas balok jika panjang 34 lebar 22 dan tinggi 13

p = 34 satuan

l = 22 satuan

t = 13 satuan

Lp = (2 × p × l) + (2 × p × t) + (2 × l × t)

Lp = (2 × 34 × 22) + (2 × 34 × 13) + (2 × 22 × 12)

Lp = 1496 + 884 + 528

Lp = 2908 satuan^2