Kak tolong bantu cara penyelesaianya kak terimaksih*noted jawaban sudah ditandai​

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Kak tolong bantu cara penyelesaianya kak terimaksih*noted jawaban sudah ditandai​

Kak tolong bantu cara penyelesaianya kak terimaksih*noted jawaban sudah ditandai​

Persamaan Trigonometri

3 tan (2x – π/6) = √3

tan (2x – π/6) = 1/√3

2x – π/6 = 30° + k.360°

2x = π/6 + π/6 + k.2π

x = π/6 + k.π … (1)

2x – π/6 = 210° + k.360°

2x = π/6 + 7π/6 + k.2π

x = 2π/3 + k.π … (2)

k bilangan bulat

k = 0 → x = π/6 , 2π/3

k = 1 → x = 7π/6 , 5π/3

dan seterusnya

Interval π ≤ x ≤ 2π

HP = {7π/6 , 5π/3}