5. Jika x1 dan x2 merupakan akar persamaan 3×2^ – 9x – 3 = 0, nilai x1^ +x2^ adalah
3x² – 9x – 3 = 0
a = 3
b = -9
c = -3
x1 + x2
= -b/a
= -(-9)/3
= 3
x1 . x2
= c/a
= -3/3
= -1
x1² + x2²
= (x1 + x2)² – 2.x1.x2
= (3)² – 2(-1)
= 9 – (-2)
= 9 + 2
= 11
Penjelasan dengan langkah-langkah:
3x² – 9x – 3 = 0
a = 3
b = -9
c = -3
(x1)² + (x2)²
= (x1 + x2)² – 2 . x1 . x2
= (-b/a)² – 2 . c/a
= ( – (-9/3))² – 2 . (-3)/3
= 9 + 2
= 11
Detail Jawaban
Kelas 9
Mapel 2 – Matematika
Bab 9 – Persamaan Kuadrat
Kode Kategorisasi : 9.2.9