Tentukan jumlah
5p(4p-3) dan 7p(3p + 4)
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Jawaban:
5p(4p-3)=20p²-15p dan 7p(3p+4)=21p²+28p
Jawaban:
5p(4p-3)=20p^2-15p
7p(3p+4)=21p^2+28p
Penjelasan dengan langkah-langkah:
5p(4p-3)=(5p×4p)-(5p×3)=
[(5×4)×(p×p)] – [(5×3)×p]=
20p^2-15p
7p(3p+4)=(7p×3p)×(7p×4)=
[(7×3)×(p×p)]+[(7×4)×p]=
[21p^2+28p