Jika (f°g) (x) = 12x-3 dan f(x) =2x -1,maka fungsi g(x) adalah

(f o g)(x) = 12x – 3
f(x) = 2x – 1
g(x) = ?

(f o g)(x) = 12x – 3
f[g(x)] = 12x – 3
2g(x) – 1 = 12x – 3
2g(x) = 12x – 3 + 1
2g(x) = 12x – 2
g(x) = (12x – 2)/2
g(x) = 2(6x – 1)/2
g(x) = 6x – 1

semoga membantu