Dik F(x) = 4x -1 dan f(3) = 20 tentukan fungsi f(x)​

Penyelesaian:

f'(x) = (4x – 1)

∫ (4x – 1) dx

= 4/2 x^2 – x + C

= 2x^2 – x + C

2x^2 – x + C = 20

2(3)^2 – 3 + C = 20

18 – 3 + C = 20

15 + C = 20

C = 5

Maka rumus fungsi

f (x) = 2x^2 – x + 5

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Detil Jawaban

Kelas: 11

Mapel: Matematika

Bab: Integral Tak Tentu Fungsi Aljabar

Kode: 11.2.10

Kata Kunci: Integral, rumus f(x)