6x²=19x-15, persamaan kuadrat​

6x² = 19x – 15

6x² – 19x + 15 = 0

6x² – 9x – 10x + 15 = 0

3x(2x – 3) – 5(2x – 3) = 0

(3x – 5) (2x – 3) = 0

3x – 5 = 0

3x = 5

x = 5/3

2x – 3 = 0

2x = 3

x = 3/2

Jadi, akar-akarnya = 5/3 dan 3/2

Penjelasan dengan langkah-langkah:

6x²-19x+15=0

(3x+5)(2x+3)=0

x=-5/3 x=-3/2