Cara mencari 6 suku pertama deret geometri gimana?

Cara mencari 6 suku pertama deret geometri gimana?

Un= 2^(2n-1)

$u1 =a = {2}^{2 times 1 - 1} = 2 \ u2 = {2}^{2 times 2 - 1} = 8 \ \ u2 = a times r \ 8 = 2 times r \ r = 4$
$sn = frac{a( {r}^{n} - 1) }{r - 1} \ s6 = frac{2( {4}^{6} - 1)}{4 - 1} = frac{2 times 4095}{3} = 2730$
jawaban: C