Jika f(x) = 3× – 2 dan (g)x = x + 1 per x – 1 jika (fog) (a) = 2, maka a =​

Penjelasan dengan langkah-langkah:

(fog) (a) = 2

f (g(a)) = 2

f ((a + 1)/(a – 1)) = 2

3 ((a + 1)/(a – 1)) – 2 = 2

(3a + 3)/(a – 1) = 2 + 2

(3a + 3)/(a – 1) = 4

3a + 3 = 4 . (a – 1)

3a + 3 = 4a – 4

3a – 4a = -4 – 3

-a = -7

a = 7