PLEASE BANTUIN AKU YA

-1/f = 1/So + 1/S’
-1/10 =1/15+1/s’
-1/s’ = 1/15 + 1/10
-1/s’ =2/30 + 3/30
-1/s’= 5/30
s’ = -30/5 = -6 cm

jarak banyangan 6 cm dibelakang cermin

perbesarannya s'/so = 6/15 = 0.4 kali

tingginya M x To = 0,4 x 5 = 2 cm

Jarak bayangan
1/s1 + 1/s0 = 1/f
1/s1 + 1/15 = 1/10
1/s1 = 1/10 – 1/15 = 3/30 – 2/30 = 1/30
jd jarak bayangan 30 cm

pembesaran bayangan
M= s1/s0 = 30/15 = 2 kali

tinggi bayangan
h1 = M x h0 = 2 x 5 = 10 cm

semoga membantu…