5x gaada yang jawab nih… huhuhu TOLONG BANTU YAA PLEASE KELAS 8 MATERI CAHAYA ‘CERMIN CEMBUNG’

Dik h = 5cm
s=15cm
f 10 cm
cermin cembung(-)
1/15+1/s'=1/-10
1/s'=1/-10 – 1/-15
s'= -6cm (ralat yg tadi)
m=6/15
=2/5×
2/5=h'/5
h'=2cm

Temennya barusan nanya, di link 6126209

-1/f = 1/So + 1/S’
-1/10 =1/15+1/s’
-1/s’ = 1/15 + 1/10
-1/s’ =2/30 + 3/30
-1/s’= 5/30
s’ = -30/5 = -6 cm

jarak banyangan 6 cm dibelakang cermin
perbesarannya = S'/So= 6/15 = 0.4 kali
tingginya = M x To = 0,4 x 5 = 2 cm

S' = jarak bayangan
So = Jarak benda
To = Tinggi benda
M = perbesaran
F= Titik api/fokus