Suku ke 11 dari barisan 256,128,64

Bab Deret Geometri

a = 256
r = 1/2

U11
= a•r^n-1
= 256 • ½^10
= 256 • ½•½•½•½•½•½•½•½•½•½
= 256 • 1/1.024
= 256/1.024
= 1/4

Barisan geometri

a = 256
r = 1/2

U11 = ar^(n – 1)
U11 = 256 . (1/2)^(11 – 1)
U11 = 256 . (1/2)^(10)
U11 = 256 . 1/1024
U11 = 1/4

semoga membantu