HNO3
Na2SO4
Fe3(PO4)2
Jika diketahui Ar H =1, O = 16, N = 14, S = 32, P =31, Fe = 56, Na = 23
Hitunglah Mr senyawa berikut ini :
Jawaban:
A. Mr HNO3 = (1×1) + (1×14) + (3×16)
= 1+14+48 = 63
B. Mr Na2SO4 = (2×23) +(1×32) + (4×16)
= 46+32+64 = 142
C. Xxxxxxxxxx
Semoga membantu 🙂