Dengan caranya terimakasih
#F
(8) lim(x->0) ( 2 x tan 3x) / (1 – cos² x)
= lim(x->0) (2x tan 3x)/ (sin² x) = (2x)(3x) /(x²)= 6x²/x² = 6
(9) lim(x->0) ( 2 sin² 2x , sin x ) / (x². tan 3x)
= lim(x->0) (sin² 2x / x²) . lim(x->0) ( 2 sin x)/ (tan 3x)
= (2x)²/x² . (2x/3x)
= (4x²/x²) (2x/3x)
= 4(2/3)
= 8/3