4 akar 32^x+1=3 akar 4^2x-3

jika f(x) =

sqrt[3] {({ {2x}^{3} } + 3x + 3)}^{2}

maka f' (1) =

sqrt[3] {({ {2.1}^{3} } + 3.1+ 3)}^{2}

sqrt[3] {({ {2.1}^{3} } + 3.1 + 3)}^{2} \ = sqrt[3]{ {(2 + 3 + 3)}^{2 } } \ = sqrt[3]{ {8}^{2} } \ = sqrt[3]{64} \ = 4