Tentukan hasil notasi:6 3k-k2 k=1

Tentukan hasil notasi:6 3k-k2 k=1

Jawab:

Penjelasan dengan langkah-langkah:

notasi sigma

$sf sumlimits_{k = 1}^6~ 3k - k^2$

$sf = 3sumlimits_{k = 1}^6~ k - sumlimits_{k = 1}^6~ k^2$

= 3 (¹/₂)(k)(k+1) - ¹/₆ (k)(k+1)(2k+1)

= 3 (¹/₂)(6)(6+1) - ¹/₆ (6)(6+1)(2.6+1)

= (³/₂)(6)(7) - ¹/₆ (6)(7)(13)

= 63- 91

= -28