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Integral Substitusi

∫ (x-2) √(2x² -8x -5) dx
u = 2x² – 8x – 5

du = 4x – 8 dx
du = 4(x -2) dx
(x-2) dx = 1/4 du

∫(x-2)(√(2x² -8x -5) dx = ∫ 1/4 u^(1/2) du
= 1/4 (2/3)(u)^(3/2) + c
= 1/6 u √ u + c
= 1/6 (2x² -8x -5) √(2x² -8x – 5) + c