Berapa hasil operasi perpangkatan 492^5-246^5.please jawabanyya

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Berapa hasil operasi perpangkatan 492^5-246^5.please jawabanyya

Penyelesaian :

492 = 246 × 2

maka,

{492}^{5} - {246}^{5} \ = (2 times 246) ^{5} - {246}^{5} \ = {2}^{5} times {246}^{5} - {246}^{5} \ = 32 times {246}^{5} - {246}^{5} \ = (32 times {246}^{5} ) - (1 times {246}^{5} ) \ = (32 - 1) times {246}^{5} \ = 31 times {246}^{5}

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Mapel : Matematika

Kelas : IV

Materi : Operasi perpangkatan.

Semoga membantu……..

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