Jika f(x)=3x+3 dan g(x)=2x-2,maka rumus fungsi (gof)(2)
Penjelasan dengan langkah-langkah:
f(x) = 3x + 3
g(x) = 2x – 2
Ditanya : (gof)(2)?
Jawab :
gof(x)
= g(f(x))
= g(3x + 3)
= 2(3x + 3) – 2
= 6x + 6 – 2
= 6x + 4
Sehingga,
gof(2)
= 6(2) + 4
= 12 + 4
= 16
diketahui:
- f(x) = 3x + 3
- g(x) = 2x – 2
ditanya:
- (g o f)(2) = ?
(g o f)(x) = g(f(x))
(g o f)(x) = 2(3x + 3) – 2
(g o f)(x) = 6x + 6 – 2
(g o f)(x) = 6x + 4
menentukan (g o f)(2)
jawab:
(g o f)(x) = 6x + 4
(g o f)(2) = 6(2) + 4
= 12 + 4
= 16
Kesimpulannya:
(g o f)(2) = 16
semoga membantu jawabannya
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Detail jawaban:
mapel: matematika
kelas: 10
materi: fungsi
kata kunci: fungsi komposisi, (g o f)(x), nilai dari (g o f)(2)
kode soal: 2
kode kategorisasi: 10.2.3