PH larutan garamdalam 4 L larutan NH4Cl 0,01M jika kh= 10^-9 adalah​

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PH larutan garamdalam 4 L larutan NH4Cl 0,01M jika kh= 10^-9 adalah​

PH larutan garamdalam 4 L larutan NH4Cl 0,01M jika kh= 10^-9 adalah​

NH4Cl adalah garam Asam

[NH4Cl] = 0,01 M

[H+] = √(Kh * [AsamKonjugasi])

[H+] = √(10^-9 * 0,01)

[H+] = √(10^-11)

[H+] = 10^-5,5

pH = – log [H+]

pH = – log (10^-5,5)

pH = 5,5