Carilah LP kerucut r: 12 s: 21

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Carilah LP kerucut
r: 12
s: 21

》Bangun Ruang

= πr² + πrs

= π × 12 × 12 + π × 12 × 21

= π × 144 + π × 252

  • = 144π + 252π
  • = 396π cm²
  • = 1.243,44 cm²

LP = phi × r × (s + r)

LP = 3,14 × 12 × (21 + 12)

LP = 3,14 × 12 × (33)

LP = 3,14 × 12 × 33

LP = 3,14 × 396

LP = 1.243,44

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Jadi, Luas permukaan kerucut tersebut adalah 1.243,44