Q.2 log 8 + 3 log 27 – 3 log 9 = …req banh, klo ga sapi V:​

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Q.2 log 8 + 3 log 27 – 3 log 9 = …req banh, klo ga sapi V:​

✧Jawaban:

2 log 8 + 3 log 27 – 3 log 9 = …

= ²log 2³ + ³log 3³ – ³log 3²

= (1 × 3) + (1 × 3) – (1 × 2)

= 3 + 3 – 2

= 6 – 2

= 4

sf ••

 rm ^{2} log : 8 + {}^{3} log : 27 - {}^{3} log : 9

 rm = : ^{2} log : {2}^{3} + {}^{3} log : {3}^{3} -: ^3log:3^2

 rm = : 3 cdot : ^{2} log : {2} + 3cdot : {}^{3} log : {3}- 3cdot:^3log:3

 rm = : 2 cdot : cancel{ ^{2} log : {2} } + 3cdot : cancel{ {}^{3} log : {3}}- 2cdot:cancel{^3log:3}

 rm = 3+ 3 - 2

 rm = 3 + 1

 rm = 4