Tentukan bentuk sederhana Aljabar berikut :

By Admin ReiPosted on October 28, 2022

1) 5(3x + 3) – 3(3x – 5)
2) 3(2x – 4y) – 5(2x + 3y)!
3) 3x (3x – 3) – 2x (2x + 1) + x – 2)
4) (2x + 8) + (4x – 6 – 5y)
5) (3p + 2q) + (–2p – 5q + 17)
___________________

Attention !
▪ Sertai Penjelasan dengan lengkap !!!
▪ Asal =》Hapus (Poin Dicabut)

Tentukan bentuk sederhana Aljabar berikut :

Penjelasan dengan langkah-langkah:

Nomor 1

$5(3x + 3) - 3(3x - 5)$

$= 5(3x) + 5(3) - 3(3x) + 3(5)$

$= 15x + 15 - 9x + 15$

$= 15x - 9x + 15 + 15$

${ boxed{ boxed{ rm = 6x + 30}}}$

Nomor 2

$3(2x - 4y) - 5(2x + 3y)$

$= 3(2x) - 3(4y) - 5(2x) - 5(3y)$

$= 6x - 12y - 10x - 15y$

$= 6x - 10x - 12y - 15y$

${ boxed{ boxed{ rm = - 4x - 27y}}}$

Nomor 3

$3x(3x - 3) - 2x(2x + 1) + x - 2$

$rm = 3x(3x) - 3x(3) - 2x(2x) - 2x + x - 2 \$

$= 9 {x}^{2} - 9x - 4 {x}^{2} - 2x + x - 2$

$= 9 {x}^{2} - 4 {x}^{2} - 9x - 2x + x - 2$

${ boxed{ boxed{ rm = 5 {x}^{2} - 10x - 2}}}$

Nomor 4

$(2x + 8) + (4x - 6 - 5y)$

$= 2x + 8 + 4x - 6 - 5y$

$= 2x + 4x + 8 - 6 - 5y$

$= 6x + 2 - 5y$

${ boxed{ boxed{ rm = 6x - 5y + 2}}}$

Nomor 5

$rm(3p + 2q) + ( - 2p - 5q + 17)$

$rm = 3p + 2q - 2p - 5q + 17$

$rm = 3p - 2p + 2q - 5q + 17$

${ boxed{ boxed{ rm = p - 3q + 17}}}$

1. 5(3x + 3) – 3(3x – 5)

= 15x + 15 – 9x + 15

= 15x – 9x + 15 + 15

= 6x + 30

2. 3(2x – 4y) – 5(2x + 3y)

= 6x – 12y – 10x – 15y

= 6x – 10x – 12y – 15y

= -4x – 27y

3. 3x (3x – 3) – 2x (2x + 1) + x – 2

= 9x² – 9x – 4x² – 2x + x – 2

= 9x² – 4x² – 9x – 2x + x – 2

= 5x² – 10x – 2

4. (2x + 8) + (4x – 6 – 5y)

= 2x + 8 + 4x – 6 – 5y

= 2x + 4x – 5y + 8 – 6

= 6x – 5y + 2

5. (3p + 2q) + (–2p – 5q + 17)

= 3p + 2q – 2p – 5q + 17

= 3p – 2p + 2q – 5q + 17

= 1p – 3q + 17

= p – 3q + 17

Maaf kalo salah ^_^