Tolong jawab setengah lagi yah no 1 bagian (E,F,G) sama langkah-langkahnya kak.​

E. 2y² – 5y – 3 = 0

(2y + 1)(y – 3) = 0

2y + 1 = 0

2y = -1

y = -1/2

y – 3 = 0

y = 3

maka, y = -1/2 dan y = 3

F. y² + 4y – 5 = 0

(y + 5)(y – 1) = 0

y + 5 = 0

y = -5

y – 1 = 0

y = 1

maka, y = -5 dan y = 1

G. -t² + 3t + 4 = 0

t² – 3t – 4 = 0

(t + 1)(t – 4) = 0

t + 1 = 0

t = -1

t – 4 = 0

t = 4

maka, t = -1 dan t = 4