1) 3x (4y + 2) – 3(6y – 5x)
2) 3(2y – 5x) – 5(x + 3y)!
3) 6y ( x – 3) – 2x (y + 1) + x – 2)
4) (5x + 8y) – (4y – 5 – 6y)
5) (3p + q) + (–8p – 9q + 7p)
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Attention !
▪ Sertai Penjelasan dengan lengkap !!!
▪ Asal =》Hapus (Poin Dicabut)
Tentukan bentuk sederhana Aljabar berikut :
Penjelasan dengan langkah-langkah:
Nomor 1
3x (4y + 2) – 3 ( 6y – 5x )
= 3x(4y) + 3x(2) – 3(6y) + 3(5x)
= 12xy + 6x – 18y + 15x
= 12xy + 6x + 15x – 18y
Nomor 2
3(2y – 5x) – 5(x + 3y)
= 3(2y) – 3(5x) – 5(x) – 5(3y)
= 6y – 15x – 5x – 15y
= -15x – 5x + 6y – 15y
Nomor 3
6y( x – 3 ) – 2x ( y + 1 ) + x – 2
= 6y(x) – 6y(3) – 2x(y) – 2x + x – 2
= 6xy – 18y – 2xy – x -2
Nomor 4
(5x + 8y) – (4y – 5 – 6y)
= 5x + 8y – ( -2y – 5 )
= 5x + 8y + 2y – 5
Nomor 5
(3p + q) + (–8p – 9q + 7p)
= 3p + q + ( -8p + 7p – 9q )
= 3p + q + ( -p – 9q )
= 3p – p + q – 9q
1) 3x (4y + 2) – 3(6y – 5x)
= 12xy + 6x – 18y + 15x
= 6x + 15x – 18y + 12xy
= 21x – 18y + 12xy
2) 3(2y – 5x) – 5(x + 3y)
= 6y – 15x – 5x – 15y
= -15x – 5x + 6y – 15y
= -20x – 9y
3) 6y ( x – 3) – 2x (y + 1) + x – 2
= 6xy – 18y – 2xy – 2 + x – 2
= x – 18y + 6xy – 2xy – 2 – 2
= x – 18y + 4xy – 4
4) (5x + 8y) – (4y – 5 – 6y)
= 5x + 8y – 4y + 5 + 6y
= 5x + 8y – 4y + 6y + 5
= 5x + 10y + 5
5) (3p + q) + (–8p – 9q + 7p)
= 3p + q – 8p – 9q + 7p
= 3p – 8p + 7p + q – 9q
= 2p – 8q
Maaf kalo salah ^_^