Tentukan penyelesaian atau akar sistem persamaan berikut!

1. x-y=0 dan 1/3x + 1/2y=5
x-y = 0
x = y
⅓y + ½y = 5
(2+3)y/(3X2) = 5
5y/6 = 5
y = 5 X 6/5
y = 30/5
y = x = 6
HP = {6,6}

2. x+1/2y=5 dan 1/3x-y=-3
x = 5-½y
⅓(5-½y) -y = -3
5/3 -y/6 -y = -3
-y/6 -6y/6 = -9/3-5/3
-7y/6 = -14/3
y = -14/3 X (-6/7)
y = 84/21
y = 4
x = 5 – (½X4)
x = 5 -2 = 3

HP = {3,4}