Tentukan akar akar persamaan kuadrat 3a²+9a=0​

3a² + 9a = 0

==> 3a (a + 3) = 0

==> a1 = 0 ==> 3 x 0 (0+3) = 0 x 3 = 0

==> a2 = -3 ==> 3 x 3 (-3 + 3) = 9 x 0 = 0

Jadi akar akar persamaan nya (0, -3)