Tentukan persanaan garis yg melalui titik C ( 4,-2 ) D ( -6, -12 )​

persamaan garis lurus (PGL)

melalui 2 titik (4,-2) dan (-6,-12)

y – y1/y2 – y1 = x – x1/x2 – x1

y – (-2)/-12 – (-2) = x – 4/-6 – 4

y + 2/-12 + 2 = x – 4/-10

y + 2/-10 = x – 4/-10

-10(x – 4) = -10(y + 2)

-10x + 40 = -10y – 20

-10x = -10y – 20 – 40

-10x = -10y – 60

-10x + 10y – 60 = 0

10x – 10y + 60 = 0

atau

10x = 10y + 60

x = y + 6