2log12-2log6+2×2log2 adalah

²log 12 – ²log 6 + 2 x ²log 2
= ²log 12/6 + 2 x 1
= ²log 2 + 2
= 1 + 2
= 3

Semoga membantu… 🙂

2log 12/6 + 2. 1 = 2log2 + 2= 1+2= 3