Nilai dari ∫_1^3(〖3x〗^2 + 2x – 1)dx​

₋₁ ³∫ 3x² + 2x – 1 dx

= [ x³ + x² – x]₋₁³

= (27+ 1) + (9- 1 ) – ( 3 +1)

=  32