4. Berapakah luas trapesium berikut ini?

AD = 5 cm

DE = 3 cm

FB = 8 cm

DC = 5 cm

CE = 8 cm ( 5 cm + 3 cm )

AE = √5² – 3²

AE = √25-9

AE = √16 = 4 cm

AE = CF = 4 cm

AE = 8 cm

AB= 8 cm + 8 cm

AB = 16 cm

Luas = Jumlah Sisi Sejajar x Tinggi : 2

Luas = (AB + CE) x CF : 2

Luas = (16 cm + 8 cm) x 4 cm : 2

Luas = 24 cm x 2

Luas = 48 cm² ✓

Jawaban:

Tinggi trapesium

= √5²-3²

=√25-9

=√16

=4cm

atas trapesium

=3+5+8

=16cm

bawah trapesium

=3+5

=8cm

Luas trapesium =(a+b)x1/2xt

=(16+8)x1/2×4

=24×1/2×4

=12×4 = 48cm²

===Semoga Membantu===