Nilai Limit ➡ 3 x – √2x + 3 / x² – 9 =A. 1/3B. 1/9C. 0D. – 1/3E. 3​

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Nilai Limit ➡ 3 x - √2x + 3 / x² - 9 =A. 1/3B. 1/9C. 0D. - 1/3E. 3​

Nilai Limit ➡ 3 x – √2x + 3 / x² – 9 =A. 1/3B. 1/9C. 0D. – 1/3E. 3​

Jawaban:

menggunakan dalil L'hospital

Penjelasan dengan langkah-langkah:

dilampirkan pada gambar

Gambar Jawaban

pake dalil l'hopital..

lim x–> 3

1 – (1/2(2x+3)^-1/2.2) / 2x

Lim x–> 3

1 – (2x+3)^(-1/2) / 2x

Lim x–> 3

1 – (1/√(2x+3) / 2x

masukkin x = 3, jadi

1 – (1/√(2.3+3) / 2(3) =

1- (1/√9) / 6 =

1- (1/3) / 6 =

(2/3) / 6 =

(2/3)*(1/6) =

2/18 =

1/9