Tentukan Nilai4! + 5! = ?Note : – ​

~Faktorial~

4! + 5!

= (4 × 3 × 2 × 1) + ( 5 × 4 × 3 × 2 × 1 )

= (24) + (120)

= 144

4! = …..

= (4 × 3 × 2 × 1)

= (12 × 2 × 1)

= (24 × 1)

= 24

5! =….

= (5 × 4 × 3 × 2 × 1)

= (20 × 3 × 2 × 1)

= (60 × 2 × 1)

= (120 × 1)

= 120

4! + 5! = ?

= 24 + 120

= 144