Tolong jawab kan bg kk

a(t) = 2t³ + 4t² – 1/2t

dit : v(2) = ..??

berarti

v(t) = v0 + integral a(t)

v(t) = 0 + integral (2t³ + 4t² – 1/2t)dt

v(t) = 1/2t^4 + (4/3)t^3 – (1/4)t^2

kecepatan saat t = 2 sekon

v(2) = 1/2.2^4 + (4/3).2^3 – (1/4).2^2

v(2) = 8 + (32/3) – 1

v(2) = (24+32-3)/3

v(2) = 53/3

v(2) = 17,67 m/s