Kuis [+50]: (a+b)(c+d) = (a–b)(c+d) = (a–b)(c–d) = (a+b)(c–d) =

Jawaban:

(a + b) (c + d) = a(c + d) + b(c + d)

= ac + ad + bc + bd

(a – b) (c + d) = a(c + d) – b(c + d)

= ac + ad – bc – bd

(a – b) (c – d) = a(c – d) – b(c – d)

= ac – ad – bc + bd

(a + b) (c – d) = a(c – d) + b(c – d)

= ac – ad + bc – bd

~Aljabar

_________

– Soal Pertama

= (a + b)(c + d)

= (b × c) + (b × d) + (a × c) + (a × d)

= bc + bd + ac + ad

…

– Soal Kedua

= (a – b)(c + d)

= (- b × c) + (- b × d) + (a × c) + (a × d)

= – bc + (- bd) + ac + ad

= – bc – bd + ac + ad

= ac + ad – bc – bd

…

– Soal Ketiga

= (a – b)(c – d)

= (- b × c) + (- b × – d) + (a × c) + (a × – d)

= – bc + bd + ac + (- ad)

= – bc + bd + ac – ad

= ac – ad – bc + bd

…

– Soal Keempat

= (a + b)(c – d)

= (a × c) + (a × – d) + (b × c) + (b × – d)

= ac + (- ad) + bc + (- bd)

= ac – ad + bc – bd

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

– Detail Jawaban

Mapel: Matematika

Kelas: VIII

Materi: Aljabar

Kode Soal: 2

Kode Kategorisasi: 8.2.1