Jika g'(x) = 4x – 5 dan g(3) = 6, tentukanlah g(x)

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Jika g'(x) = 4x – 5 dan g(3) = 6, tentukanlah g(x)

G'(x) = 4x – 5
g(x) =  2x^2 – 5x + C
g(3) = 2(3)^2 -5(3) +C
6 = 18 – 15 + C
C= 3
Jadi g (x) = 2x^2 – 5x + 3

Pakai integral
int ( 4x-5) dx = 2x² – 5x + c = g(x)

cari c nya dulu
g(3) = 6
2. 3² – 5.3 + c = 6
c = 3

g(x) = 2x² – 5x + 3