Penyelesaian dari pertidaksamaan nilai mutlak |×-2| + 10 = 12 adalah…
|x – 2| + 10 = 12
|x – 2| = 12 – 10
|x – 2| = 2
x = 2 + 2
x = 4
|x – 2| = -2
x – 2 = -2
x = -2 + 2
x = 0
Jadi, HP = {0, 4}
Penyelesaian dari pertidaksamaan nilai mutlak |×-2| + 10 = 12 adalah…
|x – 2| + 10 = 12
|x – 2| = 12 – 10
|x – 2| = 2
x = 2 + 2
x = 4
|x – 2| = -2
x – 2 = -2
x = -2 + 2
x = 0
Jadi, HP = {0, 4}