Himpunan dari( X²- 4 x +3 )pangkat x²+ 2x-15 = (2x-5)pangkat x²+2x-15
(x – 3)(x + 5) = 0
x + 5 = 0
x₁ = -5
x – 3 = 0
x₂ = 3
(x – 3)(x – 1) = 2x – 5
x² – 4x + 3 = 2x – 5
x² – 4x – 2x + 3 + 5 = 0
x² – 6x + 8 = 0
(x – 4)(x – 2) = 0
x – 2 = 0
x₃ = 2
x – 4 = 0
x₄ = 4
• Jika x = x₁ = -5 (maka (x – 3)(x + 5) = 0) :
(42)⁰ = (-15)⁰
1 = 1 (memenuhi)
Maka, x₁ = -5 → Memenuhi
• Jika x = x₂ = 3
(maka (x – 3)(x + 5) = 0 dan (x – 3)(x – 1) = 0) :
(0)⁰ = (2(3) – 5)⁰
Tidak Tedifinisi = (6 – 5)⁰
Tidak Terdifinisi = (1)⁰
Tidak Terdifinisi = 1 (Tidak memenuhi)
Maka, x₂ = 3 → Tidak memenuhi
• Jika x = x₃ = 2
( ((2) – 3)((2) – 1) )⁽² ⁻ ³⁾⁽² ⁺ ⁵⁾ = (2(2) – 5)⁽² ⁻ ³⁾⁽² ⁺ ⁵⁾
( (-1)(1) )⁽⁻¹⁾⁽⁷⁾ = (4 – 5)⁽⁻¹⁾⁽⁷⁾
(-1)⁽⁻⁷⁾ = (-1)⁽⁻⁷⁾
-1 = -1 (Memenuhi)
Maka, x₃ = 2 → Memenuhi
• Jika x = x₄ = 4 :
( ((4) – 3)((4) – 1) )⁽⁽⁴⁾ ⁻ ³⁾⁽⁽⁴⁾ ⁺ ⁵⁾
= (2(4) – 5)⁽⁽⁴⁾ ⁻ ³⁾⁽⁽⁴⁾ ⁺ ⁵⁾
( (1)(3) )⁽¹⁾⁽⁹⁾ = (8 – 5)⁽¹⁾⁽⁽⁹⁾
(3)⁹ = (3)⁹
19683 = 19683 (Memenuhi)
Maka, x₄ = 4 → Memenuhi
Kesimpulan :
x₁ = -5 → Memenuhi
x₂ = 3 → Tidak memenuhi
x₃ = 2 → Memenuhi
x₄ = 4 → Memenuhi