Faktor persamaan m² + 1 m – 12= 0​

Jawab:

(1 – m)x² + (8 – 2m)x + 12 = 0

akar kembar –> D = 0

b² – 4ac = 0

(8-2m)² – 4.(1-m).12 = 0

64 – 32m + 4m² – 48 + 48m = 0

4m² + 16m + 16 = 0  

m² + 4m + 4 = 0

(m + 2)² = 0

m + 2 = 0

m = -2.

Penjelasan dengan langkah-langkah: