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Jawaban:

Koordinat Cartesius

P (6√5, 120°)

r = 6√5 dan a° = 120°

maka,

a = r cos a° → (6√5)cos 120° → 6√5 cos (180° – 60°)

→ 6√5 (-cos 60°) → 6√5 × (-½) → -3√5

b = r sin a° → (6√5)sin 120°→ 6√5 sin (180° – 60°)

→ 6√5 (sin 60°) → 6√5 × (½√3) = 3√15

maka, Titik Koordinat P (a,b)

→ P (-3√5, 3√15)

Jawaban [ C ]