a. fog (x)
b. gof (x)
c. fog (3)
d. gof (5)
Diketahui fungsi f(x)=3x-7 dan g(x)=x2-3,tentukan
Jawaban:
a. fog (x) = 3x² – 16
b. gof (x) = 9x² – 42x + 46
c. fog (3) = 11
d. gof (5) = 22
Penjelasan dengan langkah-langkah:
a. fog (x) = f (g(x))
= f (x²-3)
f (x) = 3x-7
= 3 (x²-3) – 7
= 3x² – 9 – 7
= 3x² – 16
b. gof (x) = g (f(x))
= g (3x-7)
g (x) = x² – 3
= (3x-7)² – 3
= (3x – 7) (3x – 7) – 3
= 9x²- 21x – 21x + 49 – 3
= 9x² – 42x + 46
c. fog (3) = f (g(3))
= f (3² – 3)
= f (9 – 3)
= f (6)
f (x) = 3x – 7
= 3 (6) – 7
= 18 – 7
= 11
d. gof (5) = g (f(5))
= g (3x-7)
= g (3(5) – 7)
= g (35 – 7)
= g (28)
g (x) = x² – 3
= (5)² – 3
= 25 – 3
= 22