Simpangan baku dari data 1 3 5 6 9 12 adalah?

Simpangan baku dari data 1 3 5 6 9 12 adalah?

Rumus Simpangan Baku :

$s = sqrt{ frac{1}{n} times sigma(xi - xbar)^{2} }$

Cari terlebih dahulu xbar (rata-rata) :

$xbar = frac{1 + 3 + 5 + 6 + 9 + 12}{6} = 6$

Kita masukan rumus :

$s = sqrt{ frac{1}{6} times ({1 - 6)}^{2} + {(3 - 6)}^{2} + {(5 - 6)}^{2} + {(6 - 6)}^{2} + {(9 - 6)}^{2} + {(12 - 6)}^{2} } \ s = sqrt{ frac{1}{6} times (25 + 9 + 1 + 0 + 9 + 36)} \ s = sqrt{ frac{1}{6} times 80} \ s = sqrt{ frac{80}{6} } \ s = sqrt{frac{40}{3}} \ s = frac{sqrt{40}}{sqrt{3}} \ s = frac{2sqrt{10}}{sqrt{3}} \ s = frac{2sqrt{10}}{sqrt{3}} times frac{sqrt{3}}{sqrt{3}} \ s = frac{2sqrt{30}}{3} \ s = frac{2}{3}sqrt{30}$

Harap koreksi kembali, komen apabila ada kesalahan.
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