Diketahui f(x)=2x²+2x-1,g(x)=x+1,h(x)=4-x. tentukan (hog)of….?​

f(x) = 2x² + 2x- 1

g(x) = x + 1

h(x) = 4 – x

(hog)(x) = h(g(x))

(hog)(x) = h(x + 1)

(hog)(x) = 4 – (x + 1)

(hog)(x) = 4 – x – 1

(hog)(x) = 4 – 1 – x

(hog)(x) = 3 – x

((hog)of)(x) = (hog(f(x)))

((hog)of)(x) = (hog(2x² + 2x – 1))

((hog)of)(x) = 3 – (2x² + 2x – 1)

((hog)of)(x) = 3 – 2x² – 2x + 1

((hog)of)(x) = 3 + 1 – 2x – 2x²

((hog)of)(x) = 4 – 2x – 2x²