Tentukan nilai optimum fungsi y=2/5xkuadrat-3x+15 dan y=-3/4xkuadrat+7x-18

Y=-3/4xkuadrat+7x-18
jawab:
Y' = 0
2(-3/4) x + 7 = 0
-3/2 x + 7 = 0
– 3x + 14 = 0
– 3x = – 14
x = 14/3

nilai optimum –> y = – 3/4 (14/3)² + 7(14/3) – 18
y = – 5/3

y=2/5xkuadrat-3+15
jawab:

y = ax²+bx+c Nilai optimum pada  x = -b/(2a) A. y=2/5x²-3x+25 Nilai optimum x = -(-3)/(2.2/5) x = 3/(4/5) x= 15/4 = 3³/₄ y =2/5(15/4)²-3(15/4)+25 hitung sendiri nilai optimum y nya ya