Tolong yaa pliiisss!!!​

» Gradien a

ma = -6/4

= -3/2

» Gradien b

mb tegak lurus ma

Syarat tegak lurus=

ma x mb = -1

-3/2 x mb = -1

mb = -1 x -2/3

mb = 2/3

» Persamaan garis

y – y1 = m (x – x1)

y – 8 = 2/3 (x – 5)

3 (y – 8) = 2 (x – 5)

3y – 24 = 2x – 10

3y – 2x – 24 + 10 = 0

3y – 2x – 14 = 0

2x – 3y + 14 = 0

Jadi jawabannya B

maaf bila ada kesalahan