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InteGraL

SUb dan Parsial

(a) ∫ (x + 1) (3x² +6x -4)³ dx

= (x + 1)/(6x +6) (1/4)(3x² +6x – 4)⁴ +c

= (x + 1)/(6 (x +6)) (1/4)(3x² +6x – 4)⁴ +c

= (1/6) (1/4)(3x² +6x – 4)⁴ +c

= 1/24 (3x² +6x – 4)⁴ +c

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(b) ∫ (2x) √(2x² -5) dx = ∫ (2x)(2x² -5)^(1/2)  dx

= (2x)/(4x) (2/3)(2x² -5)^(3/2) + c

= 1/2 . 2/3. (2x² -5)√(2x² -5) + c

= 1/3 (2x² -5)√(2x² -5) + c

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(c) ∫ (x) / √(x² -4)  dx = ∫ (x) (x² – 4)^(-1/2) dx

= ( x/ 2x) (2)(x² – 4)^(1/2) + c

= (1/2) (2) √ (x² – 4) + c

=  √(x² – 4) + c

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