Tentukan nilai x

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 {2}^{1200}  +  {4}^{600}  +  {8}^{400}  +  {16}^{800}  =  {2}^{x}
tolong kaka^^​

Tentukan nilai x

2^1200 + 4^600 + 8^400 + 16^800 = 2^x

2^1200 + 2^1200 + 2^1200 + 2^3200 = 2^x

2^1200 + 2^1200 + 2^1200 + (2^1200.2^1200.2^800) = 2^x

3.2^1200 + (2^1200)² .2^800 = 2^x

2^1200 (3+2^1200.2^800) = 2^x

2^1200 (3 + 2^800.2^400.2^800) = 2^x

2^800.2^400 (3 + (2^800)².2^400) = 2^x

2^800.2^400 ((3 + 2^800) = 2^x

2^400.2^400.2^400(3 + 2^400.2^400) = 2^x

((2^400)²(3.2^400 + 1) = 2^x

2^400(3.2^400 + 2^400) = 2^x

2^400((2^400(3+1) = 2^x

2^400(2^400(4) = 2^x

2^400(2^402) = 2^x

2^(400+402) = 2^x

2^802 = 2^x

x = 802