Tolong kerjain ya,nanti dapet nomor dila

Tolong kerjain ya,nanti dapet nomor dila

Jawaban:

Luas penampang pipa

A = π.( r₂² – r₁² )

A = π/4 . ( d₂² – d₁² ) = π/4 . ( 0,15² – 0,115² )

A = 0,007285 m²

a) Perpendekan

σ = E. ε

F/A = E . δ/L

δ = F. L / A. E

δ = 620.10³. 1,2 / ( 0,007285. 200.10⁶ )

δ = 0,00051 m = 0,51 mm ( berkurangnya panjang pipa )

b) Regangan lateral

σ = F/A = 620.10³/0,007285 = 85106382.98 Pa

ε = σ/E = 85106382.98 / 200.10⁶

ε = 0,0004255

$epsilon^l =nu.epsilon\\epsilon^l = 0,3 hspace{0.1 cm}.hspace{0.1 cm} 0,0004255 = 1,27.10^{-4}$

c) Pertambahan diameter

$Delta d_1 = epsilon^lhspace{0.1 cm}.hspace{0.1 cm}d_1\\Delta d_1 =1,27.10^{-4}hspace{0.1 cm}.hspace{0.1 cm}0,115 = 1,46.10^{-5}hspace{0.1 cm}m=0,0146hspace{0.1 cm}mm\\Delta d_2 = epsilon^lhspace{0.1 cm}.hspace{0.1 cm}d_2\\Delta d_2 =1,27.10^{-4}hspace{0.1 cm}.hspace{0.1 cm}0,15 = 1,91.10^{-5}hspace{0.1 cm}m=0,0191hspace{0.1 cm}mm$