Jika a+b+c=0 makanilai (a+b)(a+c)(b+c)/abc adalah

Aljabar

a + b + c = 0

(a + b)(a + c)(b + c)/abc

= (0 – c)(0 – b)(0 – a)/abc

= (-c)(-b)(-a)/abc

= -cba/abc

= -1