Tentukanlah himpunan penyelesaian dari persamaan linear berikut

(3) 4y – 10 = 14
4y=14+10
y=24/4 =6
(4) 7a + 3 = 0
7a=3
a=3/7
(5) 8 – 4b = 6
-4b=-2
b=1/2
(6) 24y – 11 = – 20y
24y+20y=11
y=11/44
y=1/4
klo gk salah gitu

3. 4y – 10 = 14
= 4y = 14 + 10
= 4y = 24
= y = 6

4. 7a + 3 = 0
= 3 = 7a
= 3/7 = a

5. 8 – 4b = 6
= 8 – 6 = 4b
= 2 = 4b
= 1/2 = b

6. 24y – 11 = -20y
= 24y + 20y = 11
= 44y = 11
= 1/4